5x^2+5=480

Solution for 5x^2+5=480 equation:

5x^2+5=480

We move all terms to the left:

5x^2+5-(480)=0

We add all the numbers together, and all the variables

5x^2-475=0

a = 5; b = 0; c = -475;
Δ = b2-4ac
Δ = 02-4·5·(-475)
Δ = 9500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9500}=\sqrt{100*95}=\sqrt{100}*\sqrt{95}=10\sqrt{95}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{95}}{2*5}=\frac{0-10\sqrt{95}}{10}
=-\frac{10\sqrt{95}}{10}
=-\sqrt{95}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{95}}{2*5}=\frac{0+10\sqrt{95}}{10}
=\frac{10\sqrt{95}}{10}
=\sqrt{95}
$